数据库也学了好多种了有oracle,sqlsever,access,理论太多,而且不精,编一段小代码,出错不断,难得调试好了,f8之后居然啥效果都没有,自己有点眼高手低了,暂时将自己的代码放在这,以后慢慢改
create table BANK_USER (id number(10),personid varchar2(10),name varchar2(10),sex
varchar2(5),tel varchar2(12));
alter table BANK_USER modify PERSONID not null;
alter table BANK_USER rename column NAME to userNAME;
alter table BANK_USER add constraint pkkey1 primary key (personid);
insert into BANK_USER
VALUES(2,'9236565','xoy','F','1316663655')
insert into BANK_USER
VALUES(5,'165655','sky','f','11296663655')
SELECT * FROM BANK_USER
create table bank_card (id number(10),cardID number(10) not null ,password varchar2(10)
not null, money number(10));
alter table bank_card add constraint pkkey2 primary key (cardid);
insert into bank_card
values(5,093291,'066098',0)
select * from bank_card
create table bank_card_user (id number(10) default 0, userid varchar2(10),cardid number(10));
alter table bank_card_user add constraint fkkey1 foreign key (userid) references
bank_user (personid);
alter table bank_card_user add constraint fkkey2 foreign key (cardid) references
bank_card (cardid);
alter table bank_card_user add constraint cukey1 primary key (id);
insert into bank_card_user
values (1,'3236565',563265);
create table bank_business (id number(10),cardid number(10),inputmoney number(10) default
0 not null ,outputmoney number(10) default 0 not null ,businesstime date);
alter table bank_business add constraint pkkey3 primary key(id);
alter table bank_business add constraint fkkey3 foreign key (cardid) references bank_card
(cardid)
declare
--定义一个记录类型
type user_card_record is record(
id bank_user.id%type,
personid bank_user.personid%type,
cardid bank_card.cardid%type
);
--定义一个记录变量
aa user_card_record;
--定义三个整型变量
x number;
b number;
c number;
begin
--把表bank_card_user最大id赋值给变量 x;
--把表bank_user最大id赋值给变量 b;
select max(id) into x from bank_card_user;
select max(id) into b from bank_user;
--如果表bank_card_user的记录小于表bank_user的记录,则把 表bank_user,bank_card多余的 记录插入到表bank_card_user中
while x <= b
loop
select id,personid into aa.id ,aa.personid
from bank_user where id=x+1;
select cardid into aa.cardid
from bank_card where id=x+1;
insert into bank_card_user
values(aa.id,aa.cardid,aa.personid);
x:=x+1;
end loop;
end;
select * from bank_card_user;
select * from bank_user;
select * from bank_card;
◎欢迎参与讨论,请在这里发表您的看法、交流您的观点。
如果你想了解SEO,下面20个小问题对你恨与帮助。1,百度快照?百度搜索引擎已先预览各网站,拍下网页的快照,为用户贮存大量应急网页。百度快照功能在百度的服务器上保存了几乎所有网站的大部分页面,使您在不能链接所需网站时,百度为您暂存的网页也可救急。而且通过百度快照寻找资料要比常规链接的速度快得多。 百度快照更新越快,应该是百度蜘蛛爬的越勤快。百度爬的很勤,证明它很看重你的站。这就是为什么交换友情链接